WeeBee Company has three assembly labor dassifications: 5-1, S-2, and S-3. The three dassifications are paid $16, $19, and $22 per hour, respectively. The assembly activity for a product uses an S-2 employee who performs that task in 24 minutes. To reduce the activity cost per unit, a product engineer proposes using a low rated employee who can perform the assembly in 21 minutes. A manager proposes using a lower-rated employee who can perform the assembly in 30 minutes Which of the following provides the most cost-effective solution? a. use the S-2 employee
b. use either the 5-1 or 5-3 employee
c. use the S-3 employee
d. use the S-1 employee

b.use the S-2 employee

Explanation:

Calculation for the the most cost-effective solution

S-1S-2S-3

Time for 1 unit (in minutes)302421

Units in 1 hour 22.52.857142857

(60/30= 2)

(60/24=2.5)

(60/21=2.857142857)

Wages per hour $ 16.00$ 19.00$ 22.00

Wages per/ unit $ 8.00 $7.60 7.70

($ 16.00/2=$8)

($ 19.00/2.5=$ 7.60)

($ 22.00/2.857142857=$ 7.70)

Ranking

S-1$ 8.00 III

S-2. $7.60 I

S-3 7.70 II

Therefore based on the above Calculation the most cost-effective solution will be to use the S-2 employee

bd = 9 cm

step-by-step explanation:

in a 30°-60°-90° triangle, the ratio of side lengths is 1 : √3 : 2. that is, the longest side (hypotenuse) is twice the length of the shortest side.

all of the triangles in your geometry are 30°-60°-90° triangles. ac is the hypotenuse of δacd, and the short side of δabc.

the short side ad of δacd will be half the length of ac, so 3 cm. the hypotenuse ab of δabc will be twice the length of ac, so 12 cm. segment bd is the difference of the lengths ab and ad, so is

bd = ab -ad

bd = 12 cm - 3 cm = 9 cm

comment on side length ratios

you can figure the ratios of side lengths in a 30°-60°-90° triangle by considering the trig ratios of the angles. or you can figure the length of the altitude of an equilateral triangle of side length 2 using the pythagorean theorem.

answermarket demand;