Dennis wants to determine if the discount rate really makes any difference in the net present value of a project. He feels that if a project is acceptable at one rate of return, it will be acceptable at all rates of return. To explain why his thinking is incorrect, you are creating an example to illustrate your point. The cash flows you are using are as follows: time zero is -$71,000, years 1 through 4 are $17,500 each, and years 5 and 6 are $22,500 each. What is net present value at a discount rate of 12 percent and 17 percent

1. descriptive statistics quickly describe large amounts of data can predict future stock returns with surprising accuracy statisticians understand non-numeric information, like colors refer mainly to patterns that can be found in data 2. a 15% return on a stock means that 15% of the original purchase price of the stock returns to the seller at the end of the year 15% of the people who purchased the stock will see a return the stock is worth 15% more at the end of the year than at the beginning the stock has lost 15% of its value since it was originally sold 3. a stock purchased on january 1 cost $4.35 per share. the same stock, sold on december 31 of the same year, brought in $4.75 per share. what was the approximate return on this stock? 0.09% 109% 1.09% 9% 4. a stock sells for $6.99 on december 31, providing the seller with a 6% annual return. what was the price of the stock at the beginning of the year? $6.59 $1.16 $7.42 $5.84

Individual consumers belong to which step of choosing a target market? possible customers competition demographics communication

Myflvs -question 3 multiple choice worth 2 points)(10.04 hc)in panama city in january, high tide was at midnight. the water level at high tide was 9 feet and1 foot at low tide. assuming the next high tide is exactly 12 hours later and that the height of thewater can be modeled by a cosine curve, find an equation for water level in january for panamacity as a function of time (t).of(t) = 4 + 5of(t) = 5 cost + 4o 460) = 5 cos 1+ 4of(0) = 4 cos + 5