It has been reported that 40% of u. s. workers employed as purchasing managers are females. in a simple random sample of u. s. purchasing managers, 70 out of the 200 are females. given this information:

a. What is the population proportion, ? Ď€ 40 = U.S. worker employed as purchasing managers are females 70 females n =200 40% is the population proportion. b. What is the sample proportion, p? 70 0.35 P= 0.35 200 c. What is the standard error of the sample proportion? p = square root of (1- ) Ď Ď€ λ = square root of .40 (1 - .40) n 200 = square root of 0.00122262 = 0.04 d. In the sampling distribution of the proportion, what is the probability that a sample of this size wo proportion at least as large as that found in part (b)? n = 200 = -2.17 p = 0.035 Ď 0.04 0.4850 ÎĽ = 0.40 x = 0.35 λ op .5 + .4850 0.99

What's the rest of the problem? lol