If 150g of aluminum react with 101g of sulfuric acid what is the maximum amount of hydrogen gas that can be produced

2Al + 3H2SO4 -> 3H2 + Al2(SO4)3

First, find your limiting reactant - do this with your moles.

Have:
Al - 5.559mol
H2SO4 - 1.030mol
Need:
Al - 0.6867mol
H2SO4 - 8.339mol

Your limiting reactant is sulfuric acid, so we will use that. 

Use your mole bridge and the calculated HAVE of sulfuric acid to do this.

1.030mol * (3/3) = 1.030mol of H2

If you want it in liters, multiply that by 22.4dm^3. If you want it in grams, multiply it by 2.016. Hope this helps!

Idon’t know what the answer is i wish i could