A20.9 ml sample of 0.267 m koh solution required 29.1 ml of aqueous acetic acid solution in a titration experiment. calculate the molarity of the acetic acid solution. answer in units of m.

The molarity of the acetic acid solution is calculated as below

calculate the moles of KOH used
moles =molarity x volume
= 20.9 x0.267 = 5.58 moles

write the reaction equation

KOH + CH3COOH = CH3COOK + H2O

since  the reacting ratio between KOH to CH3COOH is 1:1 the  moles of CH3COOH is also = 5.58  moles

molarity of CH3COOH = moles/volume

=5.58 /29.1 =0.192 M

Ithinks its false. tell me if im wrong