What is the mass of strontium chloride that reacts with 300.0 g of sulfuric acid?

SrCl₂ reacts with conc. H₂SO₄ and gives SrSO₄ and 2HCl as the products. The balanced equation is
SrCl₂ + H₂SO₄ → SrSO₄ + 2HCl

moles = mass / molar mass

molar mass of  H₂SO₄ = 98 g mol⁻¹
moles of H₂SO₄ = 300.0 g / 98 g mol⁻¹ = 3.06 mol

Stoichiometric ratio between SrCl₂ and H₂SO₄ is 1 : 1
Hence, moles of SrCl₂ = moles of H₂SO₄
                                    = 3.06 mol

molar mass of SrCl₂ = 158.53 g mol⁻¹
Hence, mass of SrCl₂  = 3.06 mol x 158.53 g mol⁻¹
                                     = 485.1 g
                   
Hence, the mass of SrCl₂ needed to react with H₂SO₄ is 485.1 g
                   
                

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