Determine the molar solubility of pbso4 in pure water. ksp (pbso4) = 1.82 × 10-8. a.1.82 × 10-8 m b.1.35 × 10-4 m c.9.1 × 10-9 m d.3.31 × 10-16 m e.4.48 × 10-4 m

When PbSO₄ is added it dissociates as follows
PbSO₄ --> Pb²⁺ + SO₄²⁻
molar solubility is the number of moles of solute that can be dissolved in 1 L of solution 
if molar solubility of PbSO₄ is X, then molar solubility of Pb²⁺ is X and SO₄²⁻ is X
the formula for ksp is as follows 
ksp - solubility product constant
ksp = [Pb²⁺][SO₄²⁻]
ksp = X * X 
ksp = X²
ksp = 1.82 x 10⁻⁸ 
X² = 1.82 x 10⁻⁸ 
X = 1.35 x 10⁻⁴ M
molar solubility of PbSO₄ is 1.35 x 10⁻⁴ M
answer is b.

The correct answer is c