In the following reaction, which species is reduced? 2k+br2 yield 2k+ + 2br-

The species that is reduced in

2K + Br2 = 2K^+ + 2Br^-

is  Br2 is reduced

This is because  Br2   move from oxidation state  zero  to   oxidation state of negative  one.  K  is  been oxidized since it   move from oxidation  state  zero  to oxidation state  of  positive  one.  K  act as a reducing agent while Br2 act as  a oxidizing  agent

Since there is the same amount of agn03 in both silver chloride and silver nitrate they produce the same amount of moles. therefore silver chloride produces the same amount of silver nitrate, so your answer is 15.0 moles of silver nitrate. i hope this !

Sorry i think the answer is b