35.0 ml of acid with an unknown concentration is titrated with 24.6 ml of 0.432 m base. what is the concentration of the acid? assume the acid contributes 1 mole of (h+) ions/mole of acid and the base contributes 1 mole of (oh-) ions/mole of base. a)3.29 m b)0.615 m c)0.304 m

Since we assume both reactants have 1 equivalent of H+ and OH- ions, we can balance the moles out. The acid of concentration x will have (x M)(0.035 L) = 0.035x moles of acid. Meanwhile, for the base: (0.432 M)(0.0246 L) = 0.0106 moles of base. Since these must be equivalent:
0.035x = 0.0106x = 0.304 M

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