Write the balanced oxidation half reaction for this oxidation reduction reaction 4al(s)+3o2(g) = 2al2o3(s)

In the above reaction,

Al is undergoing oxidation, while oxygen is undergoing reduction.

The oxidation half reaction for above reaction can be written as:

Al          →                Al3+      +       3e-

However, reactant and product has 4 Al atoms, so on multiplying above reaction by 4 we get

4Al    →       4Al3+        +         12e-

Thus, above is balanced oxidation half reaction for above reaction