How many liters of nh are needed to react completely with 30.0 l of no (at stp)? the products are nitrogen gas and water. show all the work

             20 L of NH₃ at S.T.P

Solution:

The balance chemical equation is as follow,

                            4 NH₃  +  6 NO    →    5 N₂  +  6 H₂O

According to equation,

    134.4 L (6 mole) NO is required  =  89.6 L (4 moles) NH₃ gas at S.T.P
So,
                   30 L of NO will require  =  X L of NH₃ at S.T.P

Solving for X,
                      X  =  (30 L × 89.6 L) ÷ 134.4 L

                      X  =  20 L of NH₃ at S.T.P

Wish i can but don’t know this