How many moles of glucose, c h o , can be "burned" biologically when 18.2 mol of oxygen is available? c h o (s) + 6o (g) > 6co (g) + 6h o(l) show all the work

18.2

Explanation:

1) Chemical equation: C₆ H₁₂ O₆ (s) + 6O₂ (g) ---> 6CO₂ (g) + 6H₂O(l)

2) Mole ratio: 6 moles C₆ H₁₂ O₆ : 6 mol O₂

6:6 is the same that 1:1. This is, each molecule of C₆ H₁₂ O₆ is burned with one mole of O₂.

3) Conclusion:

Therefore, 18.2 moles of C₆ H₁₂ O₆ can be burned with 18.2 moles of O₂

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