How many grams of chromium are required to react with 125ml of 0.75m cuso4?

Chromium and copper (ii) sulfate react according the reaction below;
 2Cr + 3CuSO4 = 3Cu +Cr2(SO4)3
We can calculate the number of moles of CuSO4 present;
no of moles of CuSO4 = 0.75 × 0.125 = 0.09735 moles
According to the reaction the mole ratio is 2 : 3
Moles of Chromium = (0.09735 × 2)/3
                                = 0.0625 Moles
Mass of chromium = 0.0625 moles × 52 g/mole 
                               = 3.25 g of chromium

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