The specific heat for liquid ethanol is 2.46 j/(g•°c) when 655j are addedto a sample of ethanol temp rises from 18.2 to 32.8 what is the mass of the ethanol sample

Thermodynamics are very important to understand for a number of reasons. The equation we use for specific heat is:

Q = m*s*(delta T)

Where Q is the heat, m is the mass of the substance, s is the specific heat of the substance, and (delta T) is the change in temperature.

To solve this problem, we will have to manipulate our equation to solve for m. After manipulating variables, we end with:

m = Q / [s * (delta T)]

Next, let’s organize ourselves and see what values the problem has given us:
- Q is 655J
- s is 2.46 J / g * °C
- (delta T) is 32.8 - 18.2 = 14.6°C
- m = ?

Now, all we need to do is plug in our values to solve for m:

m = (655J)/[(2.46J/g*°C)*(14.6°C)
m = 18.2 g

The mass of the ethanol sample is 18.2g.

Hopefully this helps you!

The answer is true for your question.