Given the equation: this equation represents the formation of a (1) fluoride ion, which is smaller in radius than a fluorine atom (2) fluoride ion, which is larger in radius than a fluorine atom (3) fluorine atom, which is smaller in radius than a fluoride ion (4) fluorine atom, which is larger is radius than a fluoride ion

Correct Option 2 and 3 i.e. (2) fluoride ion, which is larger in radius than a fluorine atom (3) fluorine atom, which is smaller in radius than a fluoride ion 

Reason:
Atomic radius of an atom/ion depends upon effective nuclear charge. Atomic radius and effective nuclear charge has inverse relation. When an electron added in a atom, as in the case of F  +  e-    →    F-, the effective nuclear charge decreases. This is because, in F atom there are 9 protons and 9 electrons, while in F- ion there are 9 protons and 10 electrons. Since, effective nuclear charge has decreased, the atomic size of F- is more as compared to F atom. 

The product formed when bao and h2o  react together is                        ba(oh)2that is  bao + h2o = ba(oh)21 mole of    bao    react  1 mole of h2o  to    form  1 mole  of ba(oh)2