What is the ph of a 6.4× 10–8 m solution of hcl(aq) at 25 °c? report your answer to the hundredths place?

pH = 6.86

Explanation:

Even though HCl is a strong acid, it is so diluted in water that we have to consider the concentration of H+ ions in water.

Thus, pH will be measured after getting total [H+] (adding up [H+] from HCl and water).

[H+] of HCl is given,  6.4× 10^–8

[H+] of water is measured knowing

[H+][OH-] is found by dissosiation of water

H2O -> H+              and           O-

I          6.4× 10^–8                     0

C         +x                                  +x

E         6.4× 10^–8 + x               x

*concentration of H2O removed because its not needed

Kw = [6.4× 10^–8 + x] [x]

10^-14 = [6.4× 10^–8 + x] [x]

do the quadratics...

x= 7.30×10^-8

total [H+] = 6.4× 10^–8 + x

               = (6.4× 10^–8) + (7.30×10^-8)

               = 1.37 × 10^-7

pH = -log[total H+]

pH = -log[1.37 × 10^-7]

ph = 6.86

electron microscopy and scanning tunneling microscopes gives us a greater understanding of atoms by being able to see the atom itself, and lets us see some atomic reactions.

explanation:

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :