A3.0 l container holds a sample of hydrogen gas at 300 k and 100 kpa. if the pressure increases to 400 kpa and the volume remains constant, what will the temperature be? question 17 options:

    The  temperature will  be  1200K   if  the volume remained   constant

      calculation
 This is calculated  using   gay lussac  law  formula,  that is P1/ T1=P2/T2  since the   volume is constant
P1 =  100 Kpa
T1=  300 K
P2=  400 Kpa
T2=?

by  making  T2   the subject of the formula  T2 =( P2 xT1)/P1

T2  is therefore = (400 KPa  x 300 K)  / 100 Kpa = 1200 K