How would you prepare 500.0 ml of a 2.00 mol/l solution of hci from a concentrated solution of 12.0 mol/l?

c(desired)*V(final) = c(conc)*V(add)

V(add) = c(desired)*V(final) / c(conc) = 2*0.5 / 12 = 0.0833 cm3 = 83.3 mL of 12 M HCl needs to be added.

First add the distilled water: 416,7 mL.

Then add the conc. HCL by using an autopipette 8 times with 10.0 mL, 1 time with 3.0 mL and then 1 time with 300 microliter .

i believe it is c.) 1575 j.

answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).