Me asa what is the boiling point of a solution of ethanol, c2h5oh and sugar that contains 20.0 g of the sugar in 250 g of water?

100.95°C

Explanation:

1) The increase of the boiling point of a solution is a colligative property and its value is:

ΔTb = m × Kb × i 

2) i is the Van't Hoof constant ans for non ionic solute is 1.

3) m is the molality

m = moles of solute / Kg of solvent

moles of solute = mass in grams / molar mass

molar mass of C₂H₅OH = 2 × 12.0 g/mol + 2 × 1.0 g/mol + 16.0 g/mol + 1.0 g/mol = 43.0 g/mol


moles of solute = 20.0 g / 43.0 g/mol = 0.465 mol


m = 0.465 mol / 0.250 kg = 1.86 m

3) Kb is the molal boiling constant of the solvent.

For water Kb = 0.512 °C / mol 

4) ΔTb = 1.86m × 1 × 0.512 °C / mol = 0.95°C.

5) Boiling temperature

Tb = 100°C + 0.95°C = 100.95°C

(no3)⁻n has oxidation number x,o has oxidation number -2.(x*1 -2*3) charge of the nitrate ion, and we know that charge of the nitrate ion =-1.so,(x*1 -2*3) =-1x-6=-1x=+5answer a. +5.