Asquirrel runs at a steady rate of 0.51 m/s in a circular path around a tree. if the squirrel's centripetal acceleration is 0.43 m/s2, what is the radius of the circle? a.0.60 m b.1.2 m c.0.36 m d.0.84 m

The radius of the circle is 0.60 meters.

Explanation:

It is given that,

Speed of squirrel, v = 0.51 m/s

Centripetal acceleration,  

Let r be the radius of circle. The expression for centripetal acceleration is given by :

r = 0.60 m

So, the radius of the circle is 0.60 meters. Hence, this is the required solution.