Asolution naocl was prepared at ph 10.3. calculate the concentration of the salt formed. given ka for hocl=3.0x10^-8

First we dissociate the salt

NaOCl ⇒ Na⁺ + OCl⁻
note that [NaOCl] = [OCl⁻]

note that Na⁺ does not undergo hydrolysis so it is a spectator.
OCl⁻ can reform HOCl in an equilibrium, with OCl⁻ acting as the base.

OCl⁻ + H₂O ⇄ OH⁻ + HOCL

Ka for HOCl = 3.0x10^-8, therefore

Kb for OCL⁻ = Kw / (Ka for HOCl)
                       = 1.0 × 10⁻¹⁴ / 3.0 × 10⁻⁸
                       = 3.3 × 10⁻⁷

since Kb for OCl⁻ is given, and the pH is given, then [OCl⁻] must be found, and [OCl⁻] = [NaOCl]

convert the pH into [OH⁻]:
pOH = 14 - pH = 14 - 10.3 = 3.7
[OH⁻] = 10^(-3.7) = 1.995 × 10⁻⁴

set up equib table

          OCl⁻                + H₂O    ⇄      OH⁻        +           HOCl
  ST     x                                               0                             0
 +Δ    -1.995 × 10⁻⁴                   +1.995 × 10⁻⁴        +1.995 × 10⁻⁴

 EQ:   x -1.995 × 10⁻⁴                 1.995 × 10⁻⁴          1.995 × 10⁻⁴

Kb = [OH⁻][HOCl] / [OCl⁻]
3.3 × 10⁻⁷ = (1.995 × 10⁻⁴)² / (x -1.995 × 10⁻⁴ )
x = 1.1963 × 10⁻¹ M = [OCl⁻] = [NaOCl]

The concentration of the salt formed, NaOCl, is 1.2 × 10⁻¹ M

The independent variable is the type of music.the dependent variable is the pulse rate.the intervening variable is the age of the subject.if the mother does not like rock, her pulse is likely to not increase.the same might be true for the sister.the friend may like rap and gets excited.to establish cause/effect relationship, all of the subjects must be consistent.hope i .