What is the initial temperature of a gas if the volume changed from 1.00l to 1.10l and the final temperature was determined to be 255?

Answer is 231.8 K

Explanation
We can use Charle's law to solve this problem.

Charle's law says "at a constant pressure, the volume of a fixed amount of gas is directly proportional to its absolute temperature".

V α T 

Where V is the volume and T is the temperature in Kelvin of the gas. We can use this for two situations as,
V₁/T₁ = V₂/T₂

V₁ = 1.00 L
T₁ = ?
V₂ = 1.10 L
T₂ = 255 K (Since the unit of the given temperature is missing in the question, thought that the given temperature is in Kelvin)

By applying the formula,
1.00 L / T₁ = 1.10 L / 255 K                   
             T₁ = (1.00 L / 1.10 L) x 255 K
             T₁ = 231.8 K

Hence, the initial temperature is 231.8 K.

Assumption : the pressure of the gas is a constant. 

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