In the reaction h2so4 + 2 naoh -> na2so4 + 2h2o, an equivalence point occurs when 32.23 ml of 0.2423 m naoh is added to a 37.21 ml portion of h2so4. what is the [h2so4]?

The reaction H2SO4 + 2 NaOH -> Na2SO4 + 2H2O applies to an acid-base titration.
            moles NaOH = c · V = 0.2423 mmol/mL · 32.23 mL = 7.809329 mmol
            moles H2SO4 = 7.809329 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 3.9046645 mmol
Hence
            [H2SO4]= n/V = 3.9046645 mmol / 37.21 mL = 0.1049 M
The answer to this question is  [H2SO4] = 0.1049 M

Ibelieve y y even though i've only taken chemistry for one year