In the reaction h2so4 + 2 naoh -> na2so4 + 2h2o, an equivalence point occurs when 29.43 ml of 0.1973 m naoh is added to a 32.42 ml portion of h2so4. what is the [h2so4]?

            moles NaOH = c · V = 0.1973 mmol/mL · 29.43 mL = 5.806539 mmol
            moles H2SO4 = 5.806539 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 2.9032695 mmol
Hence
            [H2SO4]= n/V = 2.9032695 mmol / 32.42 mL = 0.08955 M
The answer to this question is  [H2SO4] = 0.08955 M

Ithink is a because if say increased in electronegativity