The reaction h2so4 + 2 naoh -> na2so4 + 2h2o applies to an acid-base tritration. the equivalence point occurs when 33.23 ml of 0.2194 m naoh is added to a 43.34 ml portion of h2so4. calculate the original [h2so4].

            moles NaOH = c · V = 0.2194 mmol/mL · 33.23 mL = 7.290662 mmol
            moles H2SO4 = 7.290662 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 3.645331 mmol
Hence
            [H2SO4]= n/V = 3.645331 mmol / 43.34 mL = 0.08411 M
The answer to this question is  [H2SO4] = 0.08411 M

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