What is the concentration of no3- ions in a solution prepared by dissolving 15.0 g of ca(no3)2 in enough water to produce 300. ml of solution?

The concentration of NO₃¯ in the solution is 0.61 M

We'll begin by calculating the number of mole in 15 g of Ca(NO₃)₂. This can be obtained as follow:

Mass of Ca(NO₃)₂ = 15 g

Molar mass of Ca(NO₃)₂ = 40 + 2[14 + (16×3)]

= 40 + 2[14 + 48]

= 40 + 2[62]

= 40 + 124

= 164 g/mol

Mole = mass / molar mass

Mole of Ca(NO₃)₂ = 15 / 164

Next, we shall determine the molarity of Ca(NO₃)₂. This can be obtained as follow:

Mole of Ca(NO₃)₂ = 0.0915 mole  

Volume = 300 mL = 300 / 1000 = 0.3 L

Molarity = mole / Volume

Molarity of Ca(NO₃)₂ = 0.0915 / 0.3

Finally, we shall determine the concentration of NO₃¯ in the 0.305 M Ca(NO₃)₂ solution. This can be obtained as follow:

From the balanced equation above,

1 mole of Ca(NO₃)₂ produced 2 moles of NO₃¯.

Therefore,

0.305 M Ca(NO₃)₂  will produce = 2 × 0.305 = 0.61 M NO₃¯

Thus, the concentration of NO₃¯ in the solution is 0.61 M

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1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation:

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-