Give the balanced equation for solid iron(iii) sulfide reacting with gaseous hydrogen chloride to form solid iron(iii) chloride and hydrogen sulfide gas.

The balanced equation for solid iron(iii) sulfide reacting with gaseous hydrogen chloride to form solid iron(iii) chloride and hydrogen sulfide gas is

Fe₂S₃(s) + 6HCl(g) → 2FeCl₃(s) + 3H₂S(g)

From the question,

We are to write the balanced equation for solid iron(iii) sulfide reacting with gaseous hydrogen chloride to form solid iron(iii) chloride and hydrogen sulfide gas.

First, we will write the chemical formula for each of the reactants and products

Iron(iii) sulfide = Fe₂S₃

Hydrogen chloride = HCl

Iron(iii) chloride = FeCl₃

Hydrogen sulfide = H₂S

Then, the balanced equation for the reaction is

Fe₂S₃(s) + 6HCl(g) → 2FeCl₃(s) + 3H₂S(g)

Hence, the balanced equation for solid iron(iii) sulfide reacting with gaseous hydrogen chloride to form solid iron(iii) chloride and hydrogen sulfide gas is Fe₂S₃(s) + 6HCl(g) → 2FeCl₃(s) + 3H₂S(g)

Learn more here: link

right

explanation:

m=9

step-by-step explanation: