Calculate the pressure of o2 (in atm) over a sample of nio at 25.00°c if δg o= 212 kj/mol for the reaction. for this calculation, use the value r = 8.3144 j/k·mol. nio(s) ⇌ ni(s) + 1/2 o2(g)

Answer : In the reaction of NiO(s) ⇌ Ni(s) + 
 
We have the given data of Δ = 212 KJ/mol
Temperature is = 25+273 = 298 K
And gas constant R = 0.008314 KJ/mol

we can use the relatinoship of gibb's free energy and remainder quotient (Q).
ΔG = Δ +RTlnQ

at equilibrium Q = K where K is equilibrim constant, and ΔG = 0;

0 = Δ + RTlnK

lnK = Δ  / (RT)

ln K = 212 / (0.00831 X 298) = 85.6 
 therefore K =  = 1.51 X

Now, K = 
So, 1.51 X =  

So, the pressure of oxygen will be = 3.87 X Pa

On converting, Pa to atm it will be 3.756 X  atm

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