What is the poh of a 0.0010 m solution of calcium hydroxide (ca(oh)2)

The pOH is: " 2.40 " .

The pOH value of a 0.0010 M solution of calcium hydroxide;

Ca(OH)₂ ; is:

" 2.40 " .

Explanation:

Calculate the pOH of a 0.0010 M solution of Ca(OH)₂ .

Note that:

"M" represents the concentration in "Molarity" ;

(that is; "moles of solute per Liter of solution" ; or, "mol / L " } ;

and that for our purposes, anything notes in "brackets" refers to "concentration"; in "M" {"Molarity" ; as explained above.}.

Note that "calcium hydroxide", that is; " Ca(OH)₂ " ;

→ dissociates into the following ions, as follows:

→ Ca(OH)₂ → Ca²⁺ + 2 OH⁻ ;

Therefore, the [OH⁻] equals: {2 * 0.0010} M = 0.0040 M .

For every Ca(OH)₂ you produce 2 OH⁻ .

Note: pOH = - log [OH⁻] ;

pOH = - log ( 0.0040) = 2.3979400086720375 ;

→ round to: " 2.40 " .

The pOH is: " 2.40 " .

The pOH value of a 0.0010 M solution of calcium hydroxide; Ca(OH)₂ ; is:

" 2.40 " .

here we have to get the change of moles on decrease the volume of the reaction in gas phase.

the   per the given options it will decrease by (d) 11-50%

we know, on decreasing the volume of the gas phase reaction the reaction moves to the product side.

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:                   1 - α               α               α           = 1 + α

(concentration = moles/volume, as volume is 1 l)

(where α is the degree of dissociation)

now the dissociation constant in terms of concentration is :

=  

or,

or,   = (at v = 1l)

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:               (1 - α)/0.5           α/0.5         α/0.5       = (1 + α)/0.5

thus, the dissociation constant in terms of concentration is :

or,  

=  

so, the change of 1 : 1/0.5

or, 1: 2

thus it will decrease by 50%.

or, as per the given options it will decrease by 11-50%

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