The equilibrium expression for a reaction is `"k"_("eq") = ("[h"^+"]"^6)/("[bi"^(2+)"]"^2["h"_ 2"s"]^3)` which of the following could be the reaction? a. 6h+(aq) + bis(s) 2bi2+(aq) + 3h2s(g) b. 2bi2+(aq) + 3h2s(aq) bi2s3(s) + 6h+(aq) c. 6h+(aq) + bi2s3(s) 2bi2+(aq) + 3h2s(g) d. 2bi2+(aq) + 3h2s(aq) bi2s3(aq) + 6h+(aq)

Option B is correct

K = Kp /Kr

The given equation indicating, the product containing 6 moles of proton whereas the reactant contains 2 mole of bismuth and 3 mole of hydrogen sulphide.

Hence, in reaction B there are 2 mole of bismuth and 3 mole of hydrogen sulphide reacting to produce 6 moles of proton. whereas the concentration of Bi2S3 is not considered as it is present in solid phase.

its going to be mutualism cuz they both benefit from the relationship.

~batmans wife dun dun

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