Areaction has an activation energy of 195.0 kj/mol. when the temperature is increased from 200. °c to 220.°c, the rate constant will increase by a factor of

The rate constant will increase by a factor of 6.5.

Using the Arrhenius equation;

ln(k2/k1) = -Ea/R(1/T2 - 1/T1)

k1 = rate constant at 200. °c

k2 = rate constant at 220.°c

Ea = Activation energy

T2 =  220.°c or 493 K

T1 = 200. °c or 473 K

Hence;

ln(k2/k1) = -195.0 × 10^3/8.314(1/493 - 1/473)

k2/k1 = 6.5

Hence;

k2 = 6.5k1

The rate constant will increase by a factor of 6.5.

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Answer : The rate constant will increase by a factor of 7.5

Explanation :

The relationship between Temperature and rate constant can be explained with the help of Arrhenius equation. The equation is given below.

㏑ (k₂/k₁) = - Ea/R ( 1/T₂ - 1/T₁)

Here k₁ & k₂ represent rate constants at temperatures T₁ and T₂

The temperature is expressed in Kelvin unit

Ea is activation energy which is expressed in J/mol

R is gas constant which is 8.314 J mol⁻¹ K⁻¹

Here we know that T₁ is initial temperature which is 200° C

To convert Celsius to Kelvin we add 273

Therefore T₁ = 200 + 273 = 473 K

T₂ = 220 + 273 = 493 K

Ea = 195 kJ/mol . We will convert kJ to J

The conversion factor is 1 kJ = 1000 J

195 kJ × (1000 J / 1 kJ) = 195000 J

So Ea = 195000 J

Let us plug in these values in Arrhenius equation now.

ln k₂/k₁ = - 195000 J mol⁻¹ / 8.314 J mol⁻¹ K⁻¹ ( 1/493 K - 1/473 K)

ln k₂/k₁ = - 23454.4 ( 0.0020284 - 0.0021142)

ln k₂/k₁ = -23454.4 × ( -8.58 × 10⁻⁵)

ln k₂/k₁ = 2.012

k₂/k₁ = e^ (2.012)

k₂/k₁ = 7.48

The above answer can be rounded to 7.5

Therefore we have k₂/k₁ = 7.5

k₂ = 7.5 k₁

We know that k₂ is the rate constant at 220° C and k₁ is the rate constant at 200°C.

Therefore we can say that the rate constant will increase by a factor of 7.5

d. temperate deciduous forest

answer: e.   sour taste

explanation: acids are those substances which dissociates in water to give ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. acids are sour in taste. example: hcl

bases are those substances which dissociates in water to give ions or accepts ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. bases are bitter in taste. bases are slippery in nature.