The primary component of the soda lime used in the experimental chamber (calcium hydroxide) reacts to produce a white precipitate. if two moles of soda lime reacts this way, how much of the precipitate will be produced?

Soda lime is a mixture primarily consisting of calcium hydroxide which is used to remove carbon dioxide gas ( CO2) from the surrounding medium.

The reaction of calcium hydroxide with carbon dioxide produces a white insoluble precipitate of calcium carbonate.

The chemical equation for the reaction is given below.

From the above equation we can see that the mole ratio of Ca(OH)₂ and CaCO₃ is 1:1 . This can be used as a conversion factor to find moles of CaCO₃ formed during the reaction

Using molar mass of CaCO3 ( MW = 100.1 g/mol) we can convert moles of CaCO3 to grams.

200.2 grams of the precipitate will be produced.

b is the correct answer

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