List the number of each type of atom on the right side of the equation hbr(aq)+2naoh(aq)→2nabr(s)+h2o(l)

On the basis of the given unbalanced equation, that is:

HBr (aq) + 2NaOH (aq) → 2NaBr (s) + H2O (l)

On the right side of the equation, there are 2 atoms of sodium (Na), 2 atoms of bromine (Br), 2 atoms of hydrogen (H), and 1 atom of oxygen (O₂).

After balancing the equation correctly we get:

HBr (aq) + NaOH (aq) → NaBr (s) + H2O (l)

On the right side, one atom of Na, 1 atom of Br, 1 atom of H and one atom of O₂.

As per the given unbalanced equation:-

HBr(aq) + 2NaOH(aq) --> 2NaBr(s) + H2O(l)

Na:-2

Br:-2

H:- 2

O:- 1

If correctly balanced then

HBr(aq) + NaOH(aq) --> NaBr(s) + H2O(l)

Na:-1

Br:-1

H:- 2

O:- 1

thats a little if u want the answer just look it up on google thats what i do haha : )

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .