If you reacted 183 grams of copper sulfate with excess iron, what mass of copper would you expect to make? you may need to balance the equation first.

The question does not provide the equation

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72.89 grams

Explanation:-

The balanced chemical equation for this reaction is

CuSO4 + Fe --> FeSO4 + Cu

Molecular weight of CuSO4 = 63.55 x 1 + 32 x 1 + 16 x 4

= 159.55 gram

Atomic weight of Cu = 63.55 gram.

According to the balanced chemical equation

1 CuSO4 gives 1 Cu

∴159.55 gram of CuSO4 would give 63.55 gram of Cu.

183 gram of CuSO4 would give 63.55 x 183 / 159.55

= 72.89 grams of Cu

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation: