What is the relative position between a methoxy group and a tert-butyl group in the product (ortho/meta/para)? why does it favor that position?

The reaction is provided in the attachment and it showing the product 4-methoxy-3-tertiarybutylanisole. In the product, first methoxy group is ortho to tertiary butyl group whereas the second methoxy is present in meta position.

The reactant 4-methoxyanisole is ortho and para directing group whereas both the para position are occupied by both the methoxy group in the ring and thus only ortho position is left with respect to each methoxy and having high electron density and therefore, the coming tertiary butyl group attach to any of the ortho position to methoxy to produce 4-methoxyanisole .

my dad did alot of meth and ace cheeks