Aballoon inflated in a room that is 34 c has a volume of 5.00 liters. the room is then heated to a temperature of 68 c. what is the new volume of the pressure remains constant?

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5.554 litres

Explanation:-

Initial Volume V 1 = 5.00 litres

Initial temperature T 1 = 34 C + 273 = 307 K

Final temperature T 2 = 68 C + 273 = 341 K

Using the relation of Charles Law (V 1 / T 1) = (V 2 / T 2)

New Volume V 2 = V1 x T2 / T1

Plugging in the values

V2 = 5.00 litres x 341 K / 307 K

= 5.554 litres.

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

the best answer is d because the strong cohesion is caused by the ability of water molecules to undergo hydrogen bonding.

a is incorrect because when water solidifies, it becomes   ice, which expands and occupies a bigger volume for the same mass of water in its liquid state.

b is incorrect because water has high surface tension. besides bonding to itself it hydrogen bonds to other molecules at the top decreasing possibility for breaking of attractive forces.

c is incorrect because the water molecule has oxygen which is highly electronegative and so pulls the electron pair towards itself creating a dipole moment, making the molecule polar.

e is incorrect because water has strong adhesion, ability to stick to other molecules such as glass because of this molecules having stronger hydrogen bonding than water.