What coefficients must be added to balance the following + so4 na2so4 + h2o 2, 1, 1, 13, 1, 1, 32, 1, 1, 24, 2, 2, 1

NaOH + H2 SO4 Na2SO4 + H2O ,

To balance this equation,

Step 1:

Balance the number of sodium on both side:

by multiplying the NaOH by 2 that is:

2NaOH+H2SO4>Na2SO4+H2O

Step2:

As NOW the number of oxygen atom and hydrogen atom are not equal on both sides. So we multiply this H2O by 2 that is:

2NaOH+H2SO4>Na2SO4+2H2O

Now the no of all atoms on product side is equal to no of all atoms in the reactant side.

so the coefficient is 2 NaOH+1 H2SO4>1 Na2SO4+2 H2O.

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.