Asolution is made by dissolving 3.8 moles of sodium chloride (nacl) in 185 grams of water. if the molal boiling point constant for water (kb) is 0.51 °c/m, what would be the boiling point of this solution? show all of the work needed to solve this problem.

The molality of the solution can be defined as moles of solute per kilogram of solvent.

Molality=3.8 moles/0.185 kg

=20.54 molal

The change in the temperature can be calculated as the product of boiling point constant and molality.

ΔTb=Kb×m=0.51 °C/m×20.54 m=10.47 °C.

The boiling point of the solution will be = 100 °C + 10.47 °C

=110.47 °C

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .