Oxidation of h2c2o4 to co2 with mno4 how many moles of electrons

Assuming the manganese IV oxide is being reduced to a manganese II ion, the answer is 10 moles of electrons.

Oxidation: 5[ C2O4(2-) -> 2 CO2 + 2e- ]
Reduction: 2[ MnO4 + 5e- + 8H+ -> Mn(2+)
+ 4H2O ]

The correct answer is "hydrogen".

Answerd. may include all of these are many definitions of bases: the  brønsted-lowry definition of acids and bases says that bases are proton acceptors.the arrhenius definition of acids and bases says that bases increase [oh⁻] in solution (thereby producing oh⁻ ions)the lewis definition of acids and bases says that bases donate electron pairs.therefore, the sensible answer is that a base may include all of the described characteristics.