Two moles of gas a spontaneously convert to three moles of gas b in a container where the temperature and pressure are held constant. the sample originally took up 10.2 l of volume. what is the new volume of the products

2A >3B

from equation 2 mol 3 mol

Volumes of the gases under the same conditions are proportional to the numbers of the moles of these gases.

n(A) : n(B) = V(A) : V(B)

V(B) = n(B)*V(A)/n(A) = 3*10.2/2 = 15.3 L

V(B)=15.3 L

i dont know the answe