What5 mass of water at 100c can be vaporized by the addition of 45 kcal of heat?

-

83.3 g of water can be vaporized by the addition of 45 kcal of heat at 100° C

Explanation: -

Heat of vaporization = 540 Cal / g.

Heat supplied = Q = 45 Kcal = 45 x 1000 Cal

Mass of water= Heat supplied / Heat of vaporization

= 45 x 1000 Cal / (540 Cal /g)

= 83.3 g

yes it is balanced

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally