Chemistry, 13.07.2019 20:00 trentonthreats5073
What mass of sodium benzoate should be added to 160.0 ml of a 0.17 m benzoic acid solution in order to obtain a buffer with a ph of 4.30?
Answers: 1
![p^{H} = p^{Ka} + log \frac{[Base]}{[Acid]}](/tpl/images/0085/9956/ee7cd.png)
![4.30 = 4.19 + log \frac{[Base]}{(0.17M)}](/tpl/images/0085/9956/72e9a.png)
![0.11 = log \frac{[Base]}{0.17}](/tpl/images/0085/9956/ef201.png)
![10^{0.11} = 10^{log \frac{[Base]}{0.17}}](/tpl/images/0085/9956/94301.png)
cancel out each other.![10^{0.11} = \frac{[Base]}{0.17}](/tpl/images/0085/9956/2d2d0.png)
![1.29 = \frac{[Base]}{0.17}](/tpl/images/0085/9956/e5ddb.png)
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What mass of sodium benzoate should be added to 160.0 ml of a 0.17 m benzoic acid solution in order...
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