How many moles of nacl are contained in 100.0 ml of a 2.0 m solution?

-

0.2 moles of NaCl are contained in 100.0 mL of a 2.0 M solution

Explanation: -

Strength of NaCl = 2.0 M

Volume of NaCl solution = 100.0 mL

=

= 0.1 L

Number of moles of NaCl = volume of NaCl x Strength of NaCl

= 0.1 L x 2.0 M

= 0.2 moles

0.2 moles of NaCl are contained in 100.0 mL of a 2.0 M solution

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).