Calculate the mass percent of a nacl solution in which 199 g of nacl is dissolved in 2.74 l of water at 25 ∘c (density = 0.997 g/ml).

Hey there!

mass of solvent :

volume in mL => 2.74 * 1000 => 2740 mL

D = m / V

0.997 = m / 2740

m = 0.997 * 2740

m = 2731.78 g of solvent

Therefore :

T % = ( mass solute / mass solute + mass solvent ) * 100

T% = ( 199 / 199 + 2731.78 ) * 100

T% = ( 199 / 2930.78 ) * 100

T% = 0.0679 * 100

T = 6.79 % of NaCl

hope this helps!

gold is my favorite solid.

substituting a hydrogen atom with a halogen in a hydrocarbon:

- the single bond remains single. a is wrong.

- the bond with hydrogen is as strong as with a halogen. c is wrong

- a hydrocarbon is saturated if there is no double bond. we do not know that so d is wrong.

- carbon will always have four valence electrons. e is wrong.

by elimination, the correct answer is b. the boiling point of the new compound increases.