Chicago uses 1.2x10^9 gallons of water/day. how many gallons per second must be pumped from the adjacent lake michigan every second to supply the city?

13,888.88 gallons per second must be pumped from the adjacent Lake Michigan every second to supply the city.

Explanation:

Gallons of water used by Chicago city in 1 day =

1 day = 24 hours

1 hour = 60 mins

1 min = 60 seconds

Gallons of water used by Chicago city in 86,400 seconds :

=

Gallons of water used by Chicago city in 1 second:

13,888.88 gallons per second must be pumped from the adjacent Lake Michigan every second to supply the city.

here we have to get the change of moles on decrease the volume of the reaction in gas phase.

the   per the given options it will decrease by (d) 11-50%

we know, on decreasing the volume of the gas phase reaction the reaction moves to the product side.

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:                   1 - α               α               α           = 1 + α

(concentration = moles/volume, as volume is 1 l)

(where α is the degree of dissociation)

now the dissociation constant in terms of concentration is :

=  

or,

or,   = (at v = 1l)

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:               (1 - α)/0.5           α/0.5         α/0.5       = (1 + α)/0.5

thus, the dissociation constant in terms of concentration is :

or,  

=  

so, the change of 1 : 1/0.5

or, 1: 2

thus it will decrease by 50%.

or, as per the given options it will decrease by 11-50%