Given the following unbalanced thermochemical equation, how many grams of carbon disulfide (cs2) will be produced along with 150.0 kj of heat? c(s) + s(s) + 89.3 kj → cs2(l)

C + 2S → CS2 + 89.3 kJ

Moles of CS2 = 150.0 kJ x (1 mol CS2/89.3 kJ) = 1.680 mol CS2

MW of CS2 = (12.01 + 2x32.06) g/mol = 76.13 g/mol

Mass of CS2 = 1.680 mol CS2 × (76.13 g CS2/1 mol CS2) = 128 g CS2

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