Chemistry, 13.07.2019 11:30 valerieaj113

32. mercury has an atomic mass of 200.59 amu. calculate the a. mass of 3.0 x 1023 atoms. b. number of atoms in one nanogram of mercury? i needed on this question

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Answer from: zahradawkins2007

a.200.59 amu of mercury contains = 6.02 * 1023 molecules

Mass for 3.0 * 1023 molecules = (3.0 * 1023 * 200.59) /6.02 * 1023

= 100.29 amu

Thus, mass for 3.0 * 1023 molecules is 100.29 amu

b.As, 200.59 g mercury contains = 6.02 * 1023 atoms

1 g mercury contains = (6.02 * 1023 /200) atoms

= 3.01 * 1021 atoms

Thus, 1 ng mercury contains = (3.01 * 1021) / 109

= 3.01 * 1012 atoms

Thus, 3.0 * 1012 atoms present in 1 ng mercury

Answer from: devenybates

a) Mass of $3.0\times 10^{23} atoms$ of mercury is 99.91 g.

b) $3.0021\times 10^{12} atoms$ in 1 nano gram of mercury.

Explanation:

$Moles(n)=\frac{\text{mass of compound}}{\text{Molar mass of compound}}$

Number of molecules or number of atoms:

$n\times N_A$

$N_A=6.022\times 10^{23}$ atoms or molecules

Mercury has an atomic mass of 200.59 amu = 200.59 g/mol

Number of mercury atoms = $3.0\times 10^{23} atoms$

Moles of Mercury :

$\frac{3.0\times 10^{23} atoms}{6.022\times 10^{23}}=0.4981 moles$

Mass of 0.4981 moles of mercury:

0.4981 moles × 200.59 amu = 99.91 g

Mass of $3.0\times 10^{23} atoms$ of mercury is 99.91 g.

b) Mass of mercury = 1 nano gram = $10^{-9} g$

Moles of mercury: $\frac{10^{-9} g}{200.59 g/mol}$

Number of atoms of mercury in 1 nano gram:

: $\frac{10^{-9} g}{200.59 g/mol}\times 6.022\times 10^{23}$

$=3.0021\times 10^{12} atoms$

Answer from: Quest

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is $1s^{2}2s^{2}2p^{6}3s^{1}$ and electronic configuration of phosphorous is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{3}$ .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

$3na + p \rightarrow na_{3}p$

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.

Electrons are transferred from atoms of to atoms of this transfer makes the sodium atoms and the

Answer from: Quest

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