In a titration experiment 12.5 ml of 0.500 m h2so4 neutralized 50.0 ml of naoh. the concentration of the naoh solution is

0.250 mol/L

Step 1. Write the chemical equation

H2SO4 + 2NaOH → Na2SO4 + 2H2O

Step 2. Calculate the moles of H2SO4

Moles of H2SO4 = 12.5 mL H2SO4 × (0.500 mmol H2SO4/1 mL H2SO4)

= 6.25 mmol H2SO4

Step 3. Calculate the moles of NaOH

Moles of NaOH = 6.25 mmol H2SO4 × (2 mmol NaOH/(1 mmol H2SO4)

= 12.5 mmol NaOH

Step 4. Calculate the concentration of the NaOH

[NaOH] = moles/litres = 12.5 mmol/50.0 mL = 0.250 mol/L

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation:

particle   p is an electron and particle q is a neutron