Calculate the concentration of an aqueous solution of naoh that has a ph of 11.98.

0.001 mol/L. The concentration of an aqueous solution of NaOH with a pH

of 11 is 0.001 mol/L

Step 1. Calculate the pOH of the solution

pOH = 14.00 – pH = 14.00 -11 = 3

Step 2. Calculate the concentration of NaOH

[NaOH] = [OH^(-)] = 10^(-pOH) mol/L = 10^(-3) mol/L = 0.001 mol/L

< > according to newton's third law of motion, forces always act in equal but opposite pairs. another way of saying this is for every action, there is an equal but opposite reaction.< >

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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