An individual suffering from high cholesterol level in her blood has 242 mg of cholesterol per 100 ml of blood. if the total blood volume of the individual is 5.2 l how many grams of total blood does the individual's body contain?

242 mg of cholesterol is present in 100 mL of blood. If the total blood present in a body is 5.2 L The total body cholesterol can be calculated as follows:

First calculate concentration as follows:

C=\frac{m}{V}=\frac{242 mg}{100 mL}=\frac{242 g}{100 L}=2.42 g/L

Now, total volume is 5.2 L thus, mass will be calculated as follows:

m=C×V=2.42 g/L×5.2 L=12.584 g

Thus, the grams of blood cholesterol in human body will be 12.584 g.

part 1: the half-life of the element is 22 years.

part 2: it will take 132.02 year for the sample to decay from 308.0 g to 4.8125 g.

explanation:

part 1: there are two ways to determine the half life time.

first way: the half life time can be determined directly from its definition as it is the time required for the sample to decay to its half concentration.

from the data the initial concentration was 45.0 g and decayed to its half value (22.5 g) in 22.0 years.

second way: the radio active decay is considered first order reaction so we can use the laws of first order reactions.

k = (1/t) ln (a/a-x), where k is the rate constant of the reaction,

t is the time of the reaction

a is the initial concentration of the reactant

a-x is the remaining concentration at time (t)

a = 45.0 g the initial concentration at t = 0 year.

at t = 22 year, a-x = 22.5 g

then k = (1/22 year) ln (45.0 g/ 22.5 g) = 0.0315 year-1.

the half-life time (t1/2) = ln 2/ k = 0.693/ k =0.693/ 0.0315 = 22 years.

part 2:

using the same law k = (1/t) ln (a/a-x),

using the given data; a = 308.0 g and a-x = 4.8125 g and the calculated k from the part 1 (k = 0.0315 year-1)

t = (1/k) ln (a/a-x) = (1/0.0315) ln (308.0/ 4.8125) = 132.02 years

nacl is added to the aqueous of what? ? in order to get a proper answer you have to specify the exact composition of the aqueous solution.